Do While i<=6
a(i)=Int(Rnd*5)+1
If a(i) Mod 2<>i Mod 2 Then
i=i-1
ElseIf a(i)<a(i-1) Then
a(i)=a(i)*2
End If
i=i+1
Loop
执行该程序段后,数组元素a(1)到a(6)的值可能是( )
for i in range(1,10,2):
print(i,end=” ”)
a=2
If a*a>3 Then
a=a-2
Print a